Wenn $x = 30^\circ$ und $y = 60^\circ$:
$\sin(30^\circ) = \frac{1}{2}$, $\cos(30^\circ) = \frac{\sqrt{3}}{2}$
$\sin(60^\circ) = \frac{\sqrt{3}}{2}$, $\cos(60^\circ) = \frac{1}{2}$
Somit ist:
$\sin(30^\circ + 60^\circ) = \frac{1}{2} \cdot \frac{1}{2} + \frac{\sqrt{3}}{2} \cdot \frac{1}{2} = \frac{1}{4} + \frac{\sqrt{3}}{4} = \frac{1 + \sqrt{3}}{4}$.